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(-1)=3G^2-5G+3
We move all terms to the left:
(-1)-(3G^2-5G+3)=0
We add all the numbers together, and all the variables
-(3G^2-5G+3)-1=0
We get rid of parentheses
-3G^2+5G-3-1=0
We add all the numbers together, and all the variables
-3G^2+5G-4=0
a = -3; b = 5; c = -4;
Δ = b2-4ac
Δ = 52-4·(-3)·(-4)
Δ = -23
Delta is less than zero, so there is no solution for the equation
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